1 条题解

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    @ 2026-10-27 5:41:08

    思路与算法

    先计算判别式 D=b²−4ac。D<0 输出 No answer!;D=0 输出 x1=x2;D>0 输出从小到大的两个实根。为了使数量级悬殊或根非常接近时仍能正确格式化,标程先把三个有限十进制数乘以共同的10的幂,得到等价整数系数 A、B、C。令 U=−sgn(A)·B、V=2|A|>0,实根即 (U±√D)/V。把根乘10⁵,用整数平方根得到其下取整,再把根与半整数的比较转为整数平方比较,最后输出固定5位小数。

    正确性说明

    统一乘共同非零尺度不改变方程的根。判别式的三分支正好对应无实根、一个重根、两个异根。V>0 后减号根不大于加号根。整数平方根 H 满足 H²≤D·10¹⁰<(H+1)²,可严格确定缩放根的整数部分;再比较根与 q+1/2,平方前单独判断符号,避免平方不等式改变方向。因此即使存在消减、下溢或很大输出,也不会依赖浮点近似来决定末位。

    复杂度

    设统一整数化后与缩放运算中最大整数有 D 个十进制数位。读入和尺度补零为 O(D),所用竖式乘法、长除法与逐两位开方均为 O(D²) 时间;只有常数次调用,因此总时间 O(D²),空间 O(D)。常规短浮点输入时可把这些数位量视作很小的常数。

    易错点

    a 可以为负,不能直接把公式的加号根认作较大根。D=0 应按精确判别式判断,不应用固定epsilon吞掉两个很近的根。注意两根即使格式化后相同,仍应走异根格式。结果为0时消去负零。数值、等号、分号之间没有空格。

    参考代码(C++11)

    #include <bits/stdc++.h>
    using namespace std;
    struct cpp_int {
        string s;
        bool neg;
        cpp_int(long long v = 0) : s(to_string(v)), neg(v < 0) {
            if (neg)
                s.erase(s.begin());
        }
        void norm() {
            auto p = s.find_first_not_of('0');
            s = p == string::npos ? "0" : s.substr(p);
            if (s == "0")
                neg = false;
        }
        static int cmpabs(const cpp_int &a, const cpp_int &b) {
            if (a.s.size() != b.s.size())
                return a.s.size() < b.s.size() ? -1 : 1;
            return a.s == b.s ? 0 : a.s < b.s ? -1 : 1;
        }
        friend bool operator<(const cpp_int &a, const cpp_int &b) {
            if (a.neg != b.neg)
                return a.neg;
            int c = cmpabs(a, b);
            return a.neg ? c > 0 : c < 0;
        }
        friend bool operator==(const cpp_int &a, const cpp_int &b) {
            return a.neg == b.neg && a.s == b.s;
        }
        friend bool operator!=(const cpp_int &a, const cpp_int &b) {
            return !(a == b);
        }
        friend bool operator>(const cpp_int &a, const cpp_int &b) {
            return b < a;
        }
        friend bool operator<=(const cpp_int &a, const cpp_int &b) {
            return !(b < a);
        }
        friend bool operator>=(const cpp_int &a, const cpp_int &b) {
            return !(a < b);
        }
        cpp_int operator-() const {
            cpp_int r = *this;
            if (r.s != "0")
                r.neg = !r.neg;
            return r;
        }
        friend cpp_int operator+(const cpp_int &a, const cpp_int &b) {
            cpp_int r;
            r.s.clear();
            int carry = 0;
            if (a.neg == b.neg) {
                int i = (int)a.s.size() - 1, j = (int)b.s.size() - 1;
                while (i >= 0 || j >= 0 || carry) {
                    int v = carry + (i >= 0 ? a.s[i--] - '0' : 0) + (j >= 0 ? b.s[j--] - '0' : 0);
                    r.s += char('0' + v % 10);
                    carry = v / 10;
                }
                r.neg = a.neg;
            } else {
                const cpp_int *x = &a, *y = &b;
                if (cmpabs(a, b) < 0)
                    swap(x, y);
                int i = (int)x->s.size() - 1, j = (int)y->s.size() - 1;
                while (i >= 0) {
                    int v = x->s[i--] - '0' - carry - (j >= 0 ? y->s[j--] - '0' : 0);
                    carry = v < 0;
                    if (carry)
                        v += 10;
                    r.s += char('0' + v);
                }
                r.neg = x->neg;
            }
            reverse(r.s.begin(), r.s.end());
            r.norm();
            return r;
        }
        friend cpp_int operator-(const cpp_int &a, const cpp_int &b) {
            return a + (-b);
        }
        friend cpp_int operator*(const cpp_int &a, int b) {
            cpp_int r;
            r.s.clear();
            long long carry = 0;
            long long z = b;
            if (z < 0)
                z = -z;
            for (int i = (int)a.s.size() - 1; i >= 0; i--) {
                carry += (a.s[i] - '0') * z;
                r.s += char('0' + carry % 10);
                carry /= 10;
            }
            while (carry) {
                r.s += char('0' + carry % 10);
                carry /= 10;
            }
            reverse(r.s.begin(), r.s.end());
            r.neg = a.neg ^ (b < 0);
            r.norm();
            return r;
        }
        friend cpp_int operator/(const cpp_int &a, int b) {
            cpp_int r;
            r.s.clear();
            long long rem = 0, z = b;
            if (z < 0)
                z = -z;
            for (char c : a.s) {
                rem = rem * 10 + c - '0';
                r.s += char('0' + rem / z);
                rem %= z;
            }
            r.neg = a.neg ^ (b < 0);
            r.norm();
            return r;
        }
        cpp_int &operator+=(const cpp_int &b) {
            *this = *this + b;
            return *this;
        }
        cpp_int &operator-=(const cpp_int &b) {
            *this = *this - b;
            return *this;
        }
        cpp_int &operator*=(int b) {
            *this = *this * b;
            return *this;
        }
        friend istream &operator>>(istream &in, cpp_int &a) {
            string v;
            if (in >> v) {
                a.neg = v[0] == '-';
                if (v[0] == '-' || v[0] == '+')
                    v.erase(v.begin());
                a.s = v;
                a.norm();
            }
            return in;
        }
        friend ostream &operator<<(ostream &out, const cpp_int &a) {
            if (a.neg)
                out << '-';
            return out << a.s;
        }
    };
    
    cpp_int fromString(string s) {
        cpp_int a;
        a.neg = !s.empty() && s[0] == '-';
        if (!s.empty() && (s[0] == '-' || s[0] == '+'))
            s.erase(s.begin());
        a.s = s;
        a.norm();
        return a;
    }
    cpp_int absBig(cpp_int a) {
        a.neg = false;
        return a;
    }
    cpp_int pow10(size_t n) {
        cpp_int a;
        a.s = "1" + string(n, '0');
        return a;
    }
    cpp_int operator*(const cpp_int &a, const cpp_int &b) {
        vector<long long> d(a.s.size() + b.s.size());
        for (int i = (int)a.s.size() - 1; i >= 0; --i)
            for (int j = (int)b.s.size() - 1; j >= 0; --j)
                d[i + j + 1] += (a.s[i] - '0') * (b.s[j] - '0');
        for (int i = (int)d.size() - 1; i > 0; --i) {
            d[i - 1] += d[i] / 10;
            d[i] %= 10;
        }
        cpp_int c;
        c.s.clear();
        for (auto x : d)
            c.s += char('0' + x);
        c.neg = a.neg != b.neg;
        c.norm();
        return c;
    }
    pair<cpp_int, cpp_int> divmod(cpp_int a, cpp_int b) {
        bool sign = a.neg != b.neg, negrem = a.neg;
        a.neg = b.neg = false;
        cpp_int q, rem;
        q.s.clear();
        cpp_int mul[10];
        for (int i = 0; i < 10; ++i)
            mul[i] = b * i;
        for (char z : a.s) {
            rem = rem * 10 + (z - '0');
            int lo = 0, hi = 9;
            while (lo < hi) {
                int mi = (lo + hi + 1) / 2;
                if (mul[mi] <= rem)
                    lo = mi;
                else
                    hi = mi - 1;
            }
            q.s += char('0' + lo);
            rem -= mul[lo];
        }
        q.neg = sign;
        q.norm();
        rem.neg = negrem;
        rem.norm();
        return {q, rem};
    }
    cpp_int floorDiv(cpp_int a, const cpp_int &b) {
        auto z = divmod(a, b);
        if (a.neg && z.second != 0)
            z.first -= 1;
        return z.first;
    }
    cpp_int rootBig(const cpp_int &a) {
        cpp_int root, rem;
        string s = a.s;
        if (s.size() % 2)
            s = "0" + s;
        for (size_t i = 0; i < s.size(); i += 2) {
            rem = rem * 100 + (s[i] - '0') * 10 + s[i + 1] - '0';
            int x = 9;
            while ((root * 20 + x) * x > rem)
                --x;
            rem -= (root * 20 + x) * x;
            root = root * 10 + x;
        }
        return root;
    }
    string fixedBig(cpp_int rounded, int digits) {
        bool neg = rounded.neg;
        string s = rounded.s;
        while (s.size() <= (size_t)digits)
            s = "0" + s;
        if (digits)
            s.insert(s.size() - digits, ".");
        return (neg ? "-" : "") + s;
    }
    cpp_int roundedRational(cpp_int a, cpp_int b) {
        bool neg = a.neg != b.neg;
        a.neg = b.neg = false;
        auto q = divmod(a, b);
        if (q.second * 2 >= b)
            q.first += 1;
        q.first.neg = neg && q.first != 0;
        return q.first;
    }
    
    pair<cpp_int, long long> decimal(string s) {
        size_t ep = s.find_first_of("eE");
        long long e = 0;
        if (ep != string::npos) {
            e = stoll(s.substr(ep + 1));
            s = s.substr(0, ep);
        }
        size_t dp = s.find('.');
        if (dp != string::npos) {
            e -= (long long)(s.size() - dp - 1);
            s.erase(dp, 1);
        }
        return {fromString(s), e};
    }
    cpp_int rootRounded(cpp_int U, cpp_int V, cpp_int D, int branch) {
        cpp_int W = U * 100000, Z = D * pow10(10), H = rootBig(Z);
        bool square = H * H == Z;
        cpp_int num = W + H * branch;
        cpp_int q = floorDiv(num, V);
        if (branch < 0 && !square && divmod(num, V).second == 0)
            q -= 1;
        cpp_int T = V * (q * 2 + 1) - W * 2;
        int cmp;
        if (branch > 0) {
            if (T < 0)
                cmp = 1;
            else {
                cpp_int x = Z * 4, y = T * T;
                cmp = x == y ? 0 : (x > y ? 1 : -1);
            }
        } else {
            if (T > 0)
                cmp = -1;
            else {
                cpp_int x = T * T, y = Z * 4;
                cmp = x == y ? 0 : (x > y ? 1 : -1);
            }
        }
        if (cmp > 0 || (cmp == 0 && q >= 0))
            q += 1;
        return q;
    }
    int main() {
        ios::sync_with_stdio(false);
        cin.tie(nullptr);
        string s[3];
        for (auto &x : s)
            cin >> x;
        auto a = decimal(s[0]), b = decimal(s[1]), c = decimal(s[2]);
        long long e = min(a.second, min(b.second, c.second));
        cpp_int A = a.first * pow10(a.second - e), B = b.first * pow10(b.second - e),
                C = c.first * pow10(c.second - e);
        cpp_int D = B * B - A * C * 4;
        if (D < 0) {
            cout << "No answer!\n";
            return 0;
        }
        cpp_int U = A.neg ? B : -B, V = absBig(A) * 2;
        if (D == 0)
            cout << "x1=x2=" << fixedBig(roundedRational(U * 100000, V), 5) << '\n';
        else
            cout << "x1=" << fixedBig(rootRounded(U, V, D, -1), 5)
                 << ";x2=" << fixedBig(rootRounded(U, V, D, 1), 5) << '\n';
    }
    
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